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MathsMediumClass 12
Tangent & Normal — Conditions, equations
Conic Sections
8
JEE Qs
8%
Hard
75
min
Master all three forms (point, slope, parametric) of tangent and normal equations for each conic, as the most efficient approach often depends on the specific problem's context.
🧮 Key Formulas
Equation of Tangent to y=f(x) at (x1, y1): y - y1 = (dy/dx)|_(x1,y1) * (x - x1)
Equation of Normal to y=f(x) at (x1, y1): y - y1 = -1 / (dy/dx)|_(x1,y1) * (x - x1)
Condition for y=mx+c to be tangent to Circle x^2 + y^2 = a^2: c = ±a*sqrt(1+m^2)
Tangent to Circle x^2 + y^2 = a^2 at (x1, y1): x*x1 + y*y1 = a^2
Tangent to Circle x^2 + y^2 = a^2 in Slope form: y = mx ± a*sqrt(1+m^2)
Normal to Circle x^2 + y^2 = a^2 at (x1, y1): y*x1 - x*y1 = 0 (passes through origin)
Condition for y=mx+c to be tangent to Parabola y^2 = 4ax: c = a/m
Tangent to Parabola y^2 = 4ax at (x1, y1): y*y1 = 2a(x + x1)
Tangent to Parabola y^2 = 4ax in Slope form: y = mx + a/m
Tangent to Parabola y^2 = 4ax in Parametric form (at^2, 2at): yt = x + at^2
Normal to Parabola y^2 = 4ax at (x1, y1): y - y1 = (-y1 / 2a)(x - x1)
Normal to Parabola y^2 = 4ax in Parametric form (at^2, 2at): y + tx = 2at + at^3
Condition for y=mx+c to be tangent to Ellipse x^2/a^2 + y^2/b^2 = 1: c^2 = a^2*m^2 + b^2
Tangent to Ellipse x^2/a^2 + y^2/b^2 = 1 at (x1, y1): x*x1/a^2 + y*y1/b^2 = 1
Tangent to Ellipse x^2/a^2 + y^2/b^2 = 1 in Slope form: y = mx ± sqrt(a^2*m^2 + b^2)
Tangent to Ellipse x^2/a^2 + y^2/b^2 = 1 in Parametric form (a*cosθ, b*sinθ): x*cosθ/a + y*sinθ/b = 1
Normal to Ellipse x^2/a^2 + y^2/b^2 = 1 at (x1, y1): a^2*x/x1 - b^2*y/y1 = a^2 - b^2
Normal to Ellipse x^2/a^2 + y^2/b^2 = 1 in Parametric form (a*cosθ, b*sinθ): a*x*secθ - b*y*cosecθ = a^2 - b^2
Condition for y=mx+c to be tangent to Hyperbola x^2/a^2 - y^2/b^2 = 1: c^2 = a^2*m^2 - b^2
Tangent to Hyperbola x^2/a^2 - y^2/b^2 = 1 at (x1, y1): x*x1/a^2 - y*y1/b^2 = 1
Tangent to Hyperbola x^2/a^2 - y^2/b^2 = 1 in Slope form: y = mx ± sqrt(a^2*m^2 - b^2)
Tangent to Hyperbola x^2/a^2 - y^2/b^2 = 1 in Parametric form (a*secθ, b*tanθ): x*secθ/a - y*tanθ/b = 1
Normal to Hyperbola x^2/a^2 - y^2/b^2 = 1 at (x1, y1): a^2*x/x1 + b^2*y/y1 = a^2 + b^2
Normal to Hyperbola x^2/a^2 - y^2/b^2 = 1 in Parametric form (a*secθ, b*tanθ): a*x*cosθ + b*y*cotθ = a^2 + b^2
Equation of Chord of Contact (T=0 form for an external point (x1, y1)): S1 = x*x1 + y*y1 - a^2 = 0 for circle x^2+y^2=a^2, similar for other conics.
✅ Key Points for JEE
- 1The derivative dy/dx gives the slope of the tangent at a given point on a curve; the slope of the normal is the negative reciprocal.
- 2The 'T=0' method (replacing x^2 with x*x1, y^2 with y*y1, 2x with x+x1, 2y with y+y1, 2xy with x*y1+y*x1) directly gives the equation of the tangent at a point (x1, y1) on the conic.
- 3For problems involving tangents from an external point, either use the slope form (y=mx+c) with the condition of tangency or assume the point of tangency (x1, y1) and use the T=0 form.
- 4Normal to a circle always passes through its center.
- 5Understanding the specific conditions of tangency (c = a/m for parabola, c^2 = a^2m^2+b^2 for ellipse, etc.) is crucial for solving problems involving tangent lines of a given slope.
⚠️ Common Mistakes
- ✕Confusing the signs in slope forms or normal equations, especially for hyperbola and ellipse.
- ✕Incorrectly calculating dy/dx for implicit functions or making algebraic errors in simplification.
- ✕Applying the T=0 method for a point not on the curve (T=0 is for tangent at a point on the curve, or chord of contact from an external point, or polar of a point).
- ✕Forgetting that for a normal, the product of slopes of tangent and normal is -1, especially when dealing with vertical tangents (horizontal normals) or horizontal tangents (vertical normals).
📝 Practice Questions
See allQ70.Let S = {(x, 1}, where (1) An ellipse whose eccentricity is 1 , when (2) A hyperbola whose eccentricity is 2 , when √r+1 √r+1 r > 1. 0 < r < 1. (3) (4) A hyperbola whose eccentricity is 2 , when An ellipse whose eccentricity is , when √1−r √ r+12 r > 1 0 < r < 1
2019·MCQHard
Q69.If the common tangents to the parabola, x2 = 4y and the circle, x2 + y2 = 4 intersect at the point P , then the distance of P from the origin (units), is: + (1) 2(3 2√2) (2) 3 + 2√2 + (3) √2 + 1 (4) 2(√2 1) JEE Main 2017 (08 Apr Online) JEE Main Previous Year Paper
2017·Multi conceptHard
NCERT Chapters
- Class 11 Maths Ch 11: Conic Sections
- Class 12 Maths Ch 6: Application of Derivatives