Equation of Line ā Symmetric, parametric form
3D Geometry
16
JEE Qs
8%
Hard
75
min
Master the parametric form to efficiently represent any point on a line, simplifying problems involving intersections, distances, and conditions on points.
š§® Key Formulas
ā Key Points for JEE
- 1The parametric form (x1+λa, y1+λb, z1+λc) allows representing any arbitrary point on the line, which is critical for solving problems involving distances, intersections, or specific conditions.
- 2The parameter Ī» in the parametric form represents a scaled distance along the line from the initial point (x1, y1, z1); if a, b, c are direction cosines, then |Ī»| is the actual distance.
- 3To convert between vector form r_vec = a_vec + λb_vec and Cartesian symmetric/parametric forms: a_vec gives the fixed point's coordinates (x1, y1, z1), and b_vec gives the direction ratios (a, b, c).
- 4If any direction ratio (a, b, or c) is zero, the symmetric form cannot have that term in the denominator. Instead, that numerator term is set to zero (e.g., if a=0, then x - x1 = 0 and (y - y1)/b = (z - z1)/c).
- 5Direction ratios (a, b, c) define the direction of the line, while direction cosines (l, m, n) are normalized direction ratios where l^2 + m^2 + n^2 = 1. Either can be used, but direction cosines simplify distance calculations.
ā ļø Common Mistakes
- āIncorrectly writing the symmetric form when one or more direction ratios are zero (e.g., dividing by zero instead of equating the numerator to zero).
- āConfusing the coordinates of the fixed point (x1, y1, z1) with the direction ratios (a, b, c) while applying the formulas.
- āFailing to understand that Ī» is a general parameter, not necessarily the distance from the fixed point unless the direction vector is a unit vector (i.e., a, b, c are direction cosines).
- āAlgebraic errors when substituting the parametric point coordinates into equations of other geometric entities (e.g., planes, spheres) to find intersection points.
š Practice Questions
See allQ4. Let P be the foot of the perpendicular from the point (1, 2, 2) on the line L : xā11 = y+1ā1 = zā22 . Let the line ār = (ā^i + ^j ā2^k) + Ī»(^i ā^j + ^k), Ī» āR, intersect the line L at Q . Then 2(PQ)2 is equal to : (1) 25 (2) 19 (3) 29 (4) 27
Q16.Let a straight line L pass through the point P(2, ā1, 3) and be perpendicular to the lines xā12 = y+11 = zā3ā2 and xā3 1 = yā23 = z+24 . If the line L intersects the yz -plane at the point Q , then the distance between the points P and Q is : (1) ā10 (2) 2ā3 (3) 2 (4) 3
Q8. Let L1 : xā12 = yā23 = zā34 and L2 : xā23 = yā44 = zā55 be two lines. Then which of the following points lies on the line of the shortest distance between L1 and L2 ? (1) ( 143 , ā3, 223 ) (2) (ā53 , ā7, 1) (3) (2, 3, 13 ) (4) ( 83 , ā1, 13 )
Q25.Let L1 : xā13 = yā1ā1 = z+10 and L2 : xā22 = 0y = z+4α , α āR, be two lines, which intersect at the point B. If P is the foot of perpendicular from the point A(1, 1, ā1) on L2 , then the value of 26α( PB)2 is _________
Q14.The perpendicular distance, of the line xā1 2 = ā1 = z+32 from the point P(2, ā10, 1), is : (1) 6 (2) 5ā2 (3) 4ā3 (4) 3ā5
Q3. Let the position vectors of the vertices A, B and C of a tetrahedron ABCD be ^i + 2^j + ^k,^i + 3^j ā2^k and 2^i + ^j ā^k respectively. The altitude from the vertex D to the opposite face ABC meets the median line segment through A of the triangle ABC at the point E . If the length of AD is ā110 and the volume of the 3 tetrahedron is ā805 , then the position vector of E is 6ā2 (1) 12 1 (7^i + 4^j + 3^k) (2) 12 (^i + 4^j + 7^k) (3) 1 6 (12^i + 12^j + ^k) (4) 16 (7^i + 12^j + ^k)
NCERT Chapters
- Class 12 Maths Ch 11: Three Dimensional Geometry