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MathsMediumClass 12

Standard Equation — x²/a² - y²/b² = 1

Conic Sections

8

JEE Qs

8%

Hard

60

min

Master the definitions and relations for 'a', 'b', and 'e', as many problems involve interchanging these to find properties or form equations in varying contexts.

🧮 Key Formulas

x²/a² - y²/b² = 1 (Standard Equation)
b² = a²(e² - 1)
e = sqrt(1 + b²/a²) (Eccentricity)
Foci: (±ae, 0)
Vertices: (±a, 0)
Directrices: x = ±a/e
Length of Latus Rectum: 2b²/a
Equations of Asymptotes: y = ±(b/a)x
Tangent at (x1, y1): xx1/a² - yy1/b² = 1
Condition for line y = mx + c to be tangent: c² = a²m² - b²
Parametric form: (a secθ, b tanθ)

✅ Key Points for JEE

  • 1The fundamental relation b² = a²(e² - 1) is essential for deriving all properties (foci, directrices, latus rectum) from the values of 'a' and 'e'.
  • 2Asymptotes (y = ±(b/a)x) are critical lines that the hyperbola branches approach infinitely, guiding its shape and aiding in sketching.
  • 3For this specific form, the transverse axis lies along the x-axis with length 2a, and the conjugate axis lies along the y-axis with length 2b.
  • 4The eccentricity 'e' is always greater than 1 for a hyperbola, which is a defining characteristic distinguishing it from an ellipse (e < 1) and parabola (e = 1).
  • 5The geometric definition of a hyperbola is the locus of a point whose difference of distances from two fixed points (foci) is a constant (2a).

⚠️ Common Mistakes

  • Confusing the eccentricity formula for hyperbola (e = sqrt(1 + b²/a²)) with that of an ellipse (e = sqrt(1 - b²/a²)).
  • Incorrectly identifying 'a' and 'b' from the equation, especially if the equation is given in a non-standard form or if the other standard form (y²/a² - x²/b² = 1) is mixed up.
  • Errors in applying the tangency condition (c² = a²m² - b²) due to incorrect signs or confusing it with the ellipse condition.
  • Mixing up the coordinates of foci (±ae, 0) and vertices (±a, 0) or their respective signs.

NCERT Chapters

  • Class 11 Maths Ch 11: Conic Sections