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Zener Diode — Voltage regulation

Semiconductor

11

JEE Qs

8%

Hard

60

min

Always check the operating conditions of the Zener diode (is it in breakdown? is I_Z within limits?) before applying Zener regulation principles to solve problems.

🧮 Key Formulas

V_out = V_Z (when Zener is in breakdown)
I_S = (V_in - V_Z) / R_S (current through series resistor)
I_S = I_Z + I_L (Kirchhoff's Current Law at the junction)
I_L = V_Z / R_L (current through load resistor)
P_Z_max = V_Z * I_Z_max (Maximum power dissipation in Zener)
R_S_min = (V_in_max - V_Z) / (I_Z_max + I_L_min) (for varying input voltage and load current)
R_S_max = (V_in_min - V_Z) / (I_Z_min + I_L_max) (for varying input voltage and load current)

✅ Key Points for JEE

  • 1A Zener diode is specifically designed to operate in the reverse breakdown region, maintaining a nearly constant voltage (Zener voltage, V_Z) across itself despite significant changes in current flowing through it.
  • 2The series resistor (R_S) is essential in a Zener regulator circuit to limit the total current, drop the excess input voltage, and protect the Zener diode from overcurrent.
  • 3For effective voltage regulation, the Zener diode must remain in its reverse breakdown region, meaning the input voltage (V_in) must be sufficiently high (V_in > V_Z) and the Zener current (I_Z) must be between its minimum knee current (I_Z_min) and maximum permissible current (I_Z_max).
  • 4Zener regulators provide both line regulation (stabilizing output despite input voltage variations) and load regulation (stabilizing output despite load current variations), by shunting excess current through the Zener diode.

⚠️ Common Mistakes

  • Assuming the Zener diode is always in breakdown without verifying the conditions (V_in > V_Z and sufficient current to cross I_Z_min).
  • Incorrectly applying Kirchhoff's Laws (KVL/KCL) or Ohm's law to different parts of the Zener regulator circuit, especially regarding current division between Zener and load.
  • Ignoring the Zener's maximum power dissipation limit (P_Z_max) or minimum current (I_Z_min), leading to circuit failure or non-regulation.

📝 Practice Questions

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2025·MCQMedium

Q43.Which of the following circuits has the same outpur as that of the given circuit? (1) (2) (3) (4)

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Q33.Which of the following circuits represents a forward biased diode? Choose the correct answer from the options given below : (1) (A) and (D) only (2) (B), (D) and (E) only (3) (C) and (E) only (4) (B), (C) and (E) only

2025·ConceptualEasy

Q26. A B Y 0 0 1 0 1 1 1 0 0 1 1 1 To obtain the given truth table, following logic gate should be placed at G: 2025 (22 Jan Shift 2) JEE Main Previous Year Paper (1) OR Gate (2) AND Gate (3) NOR Gate (4) NAND Gate

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Q28.The output of the circuit is low (zero) for : (A) X = 0, Y = 0 (B) X = 0, Y = 1 (C) X = 1, Y = 0 (D) X = 1, Y = 1 Choose the correct answer from the options given below : (1) (B), (C) and (D) only (2) (A), (B) and (C) only (3) (A), (C) and (D) only (4) (A), (B) and (D) only

2025·MCQEasy

Q45. In the circuit shown here, assuming threshold voltage of diode is negligibly small, then voltage VAB is correctly represented by : (1) VAB would be zero at all times (2) (3) (4)

2025·MCQMedium

NCERT Chapters

  • Class 12 Physics Ch 14: Semiconductor Electronics: Materials, Devices and Simple Circuits