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MathsMediumClass 12

Asymptotes, eccentricity

Conic Sections

8

JEE Qs

8%

Hard

60

min

Master the formulas and conceptual understanding of eccentricity for all conics, and practice deriving and applying asymptote equations specifically for hyperbolas in various forms.

🧮 Key Formulas

Eccentricity (e) definition: e = c/a (where c is distance from center to focus, a is distance from center to vertex)
Relationship for Ellipse: c^2 = a^2 - b^2 OR b^2 = a^2(1 - e^2) => e = sqrt(1 - b^2/a^2) (if a > b)
Relationship for Hyperbola: c^2 = a^2 + b^2 OR b^2 = a^2(e^2 - 1) => e = sqrt(1 + b^2/a^2)
Asymptotes of Hyperbola (x^2/a^2 - y^2/b^2 = 1): y = ±(b/a)x
Asymptotes of Hyperbola (y^2/b^2 - x^2/a^2 = 1): x = ±(b/a)y
Combined equation of asymptotes for x^2/a^2 - y^2/b^2 = 1: x^2/a^2 - y^2/b^2 = 0
Angle (2θ) between asymptotes: tan(θ) = b/a, so 2θ = 2 * tan⁻¹(b/a)

✅ Key Points for JEE

  • 1Eccentricity (e) is a dimensionless parameter that defines the shape of a conic section; e = 0 for circle, 0 < e < 1 for ellipse, e = 1 for parabola, e > 1 for hyperbola.
  • 2Asymptotes are lines that a hyperbola approaches but never touches as its branches extend infinitely; they exist only for hyperbolas.
  • 3The equation of the asymptotes of a hyperbola x²/a² - y²/b² = 1 is obtained by replacing the '1' on the RHS with '0' (i.e., x²/a² - y²/b² = 0).
  • 4For a rectangular hyperbola (a = b), the asymptotes are perpendicular, and its eccentricity e = sqrt(2).
  • 5Any line parallel to an asymptote intersects the hyperbola at exactly one point.

⚠️ Common Mistakes

  • Confusing the relationship between a, b, and e for ellipses (b² = a²(1-e²)) with that for hyperbolas (b² = a²(e²-1)).
  • Incorrectly identifying 'a' and 'b' values, especially when the transverse axis is along the y-axis (y²/b² - x²/a² = 1).
  • Attempting to find asymptotes for ellipses or parabolas, as they do not have them.

NCERT Chapters

  • Class 11 Maths Ch 11: Conic Sections

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