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MathsMediumClass 11

Combinations — nCr, properties

Permutation & Combination

9

JEE Qs

8%

Hard

75

min

Master the art of distinguishing between selection and arrangement problems; this is the core skill for P&C.

🧮 Key Formulas

nCr = n! / (r! * (n-r)!)
nCr = nC(n-r)
nCr + nC(r-1) = (n+1)Cr
nC0 + nC1 + ... + nCn = 2^n
nCr = (n/r) * (n-1)C(r-1)

✅ Key Points for JEE

  • 1Combinations deal with selection of items where the order of selection does not matter; if order matters, it's a permutation.
  • 2The symmetry property nCr = nC(n-r) is highly useful for simplifying calculations and solving equations involving combinations.
  • 3Pascal's Identity, nCr + nC(r-1) = (n+1)Cr, is crucial for summing consecutive combinations or for identity proofs.
  • 4The total number of ways to select any number of items from 'n' distinct items (including selecting none) is 2^n.
  • 5Carefully identify 'n' (total items available) and 'r' (items to be selected) in problem statements, especially with conditions like 'at least' or 'at most'.

⚠️ Common Mistakes

  • Confusing combinations with permutations, leading to incorrect problem setup (e.g., using nCr when nPr is required or vice-versa).
  • Errors in applying the Addition Principle (for mutually exclusive cases) versus the Multiplication Principle (for sequential events).
  • Not correctly handling 'n' and 'r' when conditions are imposed, such as specific items always being included or excluded.
  • Algebraic mistakes when solving equations involving nCr or simplifying expressions using its properties.

NCERT Chapters

  • Class 11 Mathematics Ch 7: Permutations and Combinations