Vector Triple Product
Vectors
12
JEE Qs
8%
Hard
60
min
Master Lagrange's Identity (a x (b x c) = (a . c)b - (a . b)c) and its permutation for (a x b) x c, as it is key to simplifying complex vector expressions and solving related problems efficiently.
🧮 Key Formulas
✅ Key Points for JEE
- 1The vector triple product a x (b x c) always results in a vector quantity.
- 2The resulting vector a x (b x c) lies in the plane formed by vectors b and c, and is perpendicular to vector a.
- 3Lagrange's Identity, a x (b x c) = (a . c)b - (a . b)c, is the most crucial formula for simplifying and calculating vector triple products.
- 4The vector cross product is not associative; therefore, a x (b x c) is generally not equal to (a x b) x c.
- 5Carefully observe the order of vectors in the parentheses, as it dictates which form of Lagrange's Identity to use and affects the sign.
⚠️ Common Mistakes
- ✕Confusing the formula for a x (b x c) with (a x b) x c, leading to incorrect application of Lagrange's Identity.
- ✕Assuming associativity of the cross product, i.e., incorrectly assuming a x (b x c) = (a x b) x c.
- ✕Misinterpreting the vector triple product as a scalar quantity instead of a vector.
📝 Practice Questions
See allQ10.Let →a and →b be two unit vectors such that the angle between them is . If λ→a + 2→b and 3→a −λ→b are 3 perpendicular to each other, then the number of values of λ in [−1, 3] is : (1) 2 (2) 1 (3) 0 (4) 3 e 1 x x loge α
Q10.Let the arc AC of a circle subtend a right angle at the centre O. If the point B on the arc AC , divides the arc −−−length of arc AB 1 → → → AC such that length of arc BC = 5 , and OC = αOA + βOB , then α + √2(√3 −1)β is equal to (1) 2√3 (2) 2 −√3 (3) 5√3 (4) 2 + √3 f ∘g is
Q23.Let →c be the projection vector of →b = λ^i + 4^k, λ > 0, on the vector →a = ^i + 2^j + 2^k. If |→a + →c| = 7, then the area of the parallelogram formed by the vectors →b and →c is ________
Q4. Let a line pass through two distinct points P(−2, −1, 3) and Q , and be parallel to the vector 3^i + 2^j + 2^k. If the distance of the point Q from the point R(1, 3, 3) is 5 , then the square of the area of △PQR is equal to : (1) 148 (2) 136 (3) 144 (4) 140
Q12.Let →a = 3^i −^j + 2^k, b =→a× (^i −2^k) and→c= b × ^k. Then the projection of→c−2^j on →a is : (1) 2√14 (2) √14 (3) 3√7 (4) 2√7
Q48.Two particles are located at equal distance from origin. The position vectors of those are represented by ¯A = 2^i + 3n^j + 2^k and ¯B = 2^i −2^j + 4p^k, respectively. If both the vectors are at right angle to each other, the value of n−1 is _____ .
NCERT Chapters
- Class 12 Mathematics Ch 10: Vector Algebra