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PhysicsMediumClass 12

Rectifiers — Half wave, full wave

Semiconductor

11

JEE Qs

8%

Hard

75

min

Master the circuit diagrams, input/output waveforms, and the calculation of average/RMS values and PIV for both half-wave and full-wave rectifiers.

🧮 Key Formulas

I_m = V_m / R_L
HWR: I_dc = I_m / pi
HWR: V_dc = V_m / pi
HWR: I_rms = I_m / 2
HWR: V_rms = V_m / 2
HWR: Rectification Efficiency (eta) = 40.6%
HWR: Ripple Factor (gamma) = 1.21
HWR: Peak Inverse Voltage (PIV) = V_m
FWR: I_dc = 2 * I_m / pi
FWR: V_dc = 2 * V_m / pi
FWR: I_rms = I_m / sqrt(2)
FWR: V_rms = V_m / sqrt(2)
FWR: Rectification Efficiency (eta) = 81.2%
FWR: Ripple Factor (gamma) = 0.48
Center-tap FWR: Peak Inverse Voltage (PIV) = 2 * V_m
Bridge FWR: Peak Inverse Voltage (PIV) = V_m

✅ Key Points for JEE

  • 1A rectifier converts alternating current (AC) into pulsating direct current (DC) using semiconductor diodes which allow current flow in only one direction.
  • 2Half-wave rectifiers (HWR) pass only one half-cycle of the input AC, while full-wave rectifiers (FWR) utilize both half-cycles, leading to higher efficiency and lower ripple.
  • 3The output frequency of a HWR is equal to the input AC frequency, whereas for a FWR, it is twice the input AC frequency.
  • 4Full-wave rectifiers (both center-tap and bridge) have significantly higher DC output voltage, lower ripple factor, and better rectification efficiency compared to half-wave rectifiers.
  • 5Peak Inverse Voltage (PIV) is the maximum voltage a diode must withstand in reverse bias and is critical for selecting appropriate diodes for the rectifier circuit.

⚠️ Common Mistakes

  • Confusing the average (DC) and RMS values of current and voltage for half-wave vs. full-wave rectifiers.
  • Incorrectly calculating the Peak Inverse Voltage (PIV), especially for the center-tap full-wave rectifier where it is 2V_m.
  • Not accounting for the 0.7V (or specified V_F) forward voltage drop across each silicon diode when calculating output voltage/current in non-ideal scenarios.

📝 Practice Questions

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Q43.Which of the following circuits has the same outpur as that of the given circuit? (1) (2) (3) (4)

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Q33.Which of the following circuits represents a forward biased diode? Choose the correct answer from the options given below : (1) (A) and (D) only (2) (B), (D) and (E) only (3) (C) and (E) only (4) (B), (C) and (E) only

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Q28.The output of the circuit is low (zero) for : (A) X = 0, Y = 0 (B) X = 0, Y = 1 (C) X = 1, Y = 0 (D) X = 1, Y = 1 Choose the correct answer from the options given below : (1) (B), (C) and (D) only (2) (A), (B) and (C) only (3) (A), (C) and (D) only (4) (A), (B) and (D) only

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Q45. In the circuit shown here, assuming threshold voltage of diode is negligibly small, then voltage VAB is correctly represented by : (1) VAB would be zero at all times (2) (3) (4)

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NCERT Chapters

  • Class 12 Physics Ch 14: Semiconductor Electronics: Materials, Devices and Simple Circuits