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MathsMediumClass 12

Tangents & Normals — Slope, equations

Applications of Derivatives

15

JEE Qs

8%

Hard

75

min

Master differentiation techniques and always evaluate the derivative at the exact point of tangency to find the correct slope.

🧮 Key Formulas

Slope of tangent m_t = dy/dx |_(x1, y1)
Equation of tangent: y - y1 = m_t (x - x1)
Slope of normal m_n = -1/m_t (if m_t != 0)
Equation of normal: y - y1 = m_n (x - x1)
If tangent is horizontal, m_t = dy/dx = 0
If tangent is vertical, m_t is undefined (dx/dy = 0)
Angle θ between two curves at intersection point (x1, y1) is the angle between their tangents: tan θ = |(m1 - m2) / (1 + m1 * m2)|

✅ Key Points for JEE

  • 1The derivative dy/dx evaluated at a specific point (x1, y1) on a curve gives the slope of the tangent line to the curve at that point.
  • 2The normal line to a curve at a point is perpendicular to the tangent line at the same point. Their slopes thus satisfy m_t * m_n = -1.
  • 3When solving problems, always ensure you differentiate the given function correctly and substitute the point of tangency (x1, y1) into dy/dx to get the specific slope.
  • 4For curves defined parametrically (x=f(t), y=g(t)), the slope of the tangent is dy/dx = (dy/dt) / (dx/dt). For implicitly defined curves, use implicit differentiation.
  • 5Horizontal tangents occur where dy/dx = 0, and vertical tangents occur where dx/dy = 0 (or dy/dx is undefined).

⚠️ Common Mistakes

  • Failing to substitute the coordinates of the point of tangency into dy/dx after differentiation, leading to a general slope expression instead of a numerical value.
  • Incorrectly calculating the slope of the normal as 1/m_t instead of -1/m_t, or failing to handle cases where m_t = 0 (horizontal tangent, vertical normal) or m_t is undefined (vertical tangent, horizontal normal).
  • Using a point other than the point of tangency (x1, y1) in the point-slope form (y - y1 = m(x - x1)) for the equation of the line.

📝 Practice Questions

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NCERT Chapters

  • Class 11 Maths Ch 10: Straight Lines
  • Class 12 Maths Ch 5: Continuity and Differentiability
  • Class 12 Maths Ch 6: Applications of Derivatives

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