Q16.Suppose A and B are the coefficients of 30th and 12th terms respectively in the binomial expansion of (1 + x)2nโ1 . If 2 A = 5 B , then n is equal to : (1) 22 (2) 20 (3) 21 (4) 19
What This Question Tests
This question involves using the general term of a binomial expansion to find specific coefficients and then solving an equation based on the given ratio of these coefficients.
Concepts Tested
Formulas Used
T_(r+1) = C(N, r) * x^r * y^(N-r)
๐ NCERT Sections This Tests
12.5 โ A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 ยท Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.7 โ The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
Physics Class 12 ยท Chapter 12
12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3ร10โ11 m. What are the radii of the n = 2 and n =3 orbits?
1.3 โ Define The Following Terms:
Chemistry Class 11 ยท Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
๐ Question Details
- Chapter
- Binomial Theorem
- Topic
- General Term and Coefficients in Binomial Expansion
- Year
- 2025
- Shift
- 24 Jan Shift 2
- Q Number
- Q16
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 8: Binomial Theorem
More from this Chapter
Q89.In the binomial expansion of (a โb)n, n โฅ5 , the sum of 5th and 6th terms is zero, then ab equals (1) 5 (2) 6 nโ4 nโ5 (3) nโ5 (4) nโ4 6 5
Q90.The sum of the series 20C0 โ20C1 + 20C2 โ20C3 + โฆ โโฆ + 20C10 is (1) โ20C10 (2) 12 20C10 (3) 0 (4) 20C10
Q77.Statement-1: โnr=0(r + 1)nCr = (n + 2)2nโ1 Statement -2: โnr=0(r + 1)nCrxr = (1 + x)n + nx(1 + x)nโ1 . JEE Main 2008 JEE Main Previous Year Paper (1) Statement โ1 is false, Statement โ2 is true (2) Statement โ1 is true, Statement โ2 is true, Statement โ2 is a correct explanation for Statement โ1 (3) Statement โ1 is true, Statement โ2 is true; (4) Statement โ1 is true, Statement โ2 is false. Statement โ2 is not a correct explanation for Statement โ1.
Q65.The remainder left out when 82n โ(62)2n+1 is divided by 9 is (1) 0 (2) 2 (3) 7 (4) 8