Q49.The ion that has sp3d2 hybridization for the central atom is: (1) BrF2 - (2) ICl4 - (3) IF6 - (4) ICl2 -
What This Question Tests
This question requires calculating the steric number for the central atom in each ion to determine its hybridization based on VSEPR theory.
Concepts Tested
Formulas Used
Steric Number = (Number of bond pairs + Number of lone pairs)
📚 NCERT Sections This Tests
5.15 — Discuss The Nature Of Bonding In The Following Coordination Entities On The
Chemistry Class 11 · Chapter 5
5.15 Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory: (i) [Fe(CN)6] 4– (ii) [FeF6] 3– (iii) [Co(C2O4)3]3– (iv) [CoF6] 3–
5.16 — Draw Figure To Show The Splitting Of D Orbitals In An Octahedral Crystal Field.
Chemistry Class 11 · Chapter 5
5.16 Draw figure to show the splitting of d orbitals in an octahedral crystal field.
5.23 — Give The Oxidation State, D Orbital Occupation And Coordination Number Of
Chemistry Class 11 · Chapter 5
5.23 Give the oxidation state, d orbital occupation and coordination number of the central metal ion in the following complexes: (i) K3[Co(C2O4)3] (iii) (NH4)2[CoF4] (ii) cis-[CrCl2(en)2]Cl (iv) [Mn(H2O)6]SO4
📋 Question Details
- Chapter
- Chemical Bonding
- Topic
- Hybridization, VSEPR theory
- Year
- 2019
- Shift
- 08 Apr Shift 2
- Q Number
- Q49
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 4: Chemical Bonding
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