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MathsMediumMCQ2014 · 11 Apr Online

Q88.The plane containing the line x−1 1 = 2 = z−33 and parallel to the line x1 = y1 = 4z passes through the point: (1) (1, −2, 5) (2) (1, 0, 5) (3) (0, 3, −5) (4) (−1, −3, 0)

What This Question Tests

This question requires finding the equation of a plane by determining its normal vector using the cross product of direction vectors of two lines (one in the plane, one parallel to it) and then checking which point lies on the plane.

Concepts Tested

Equation of a planeDirection vectors of linesNormal vector (cross product)Point on a plane

Formulas Used

n = v₁ × v₂

A(x-x₁) + B(y-y₁) + C(z-z₁) = 0

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