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MathsEasyMCQ2023 · 31 Jan Shift 2

Q88.Let P be the plane, passing through the point (1, −1, −5) and perpendicular to the line joining the points (4, 1, −3) and (2, 4, 3). Then the distance of P from the point (3, −2, 2) is (1) 6 (2) 4 (3) 5 (4) 7

What This Question Tests

This is a direct application of formulas for finding the equation of a plane given a point and its normal vector (derived from the line joining two points) and subsequently calculating the distance of another point from this plane.

Concepts Tested

Equation of a plane passing through a point and perpendicular to a lineNormal vector of a planeDistance of a point from a plane

Formulas Used

Equation of plane: A(x-x_0) + B(y-y_0) + C(z-z_0) = 0

Distance = |Ax_1 + By_1 + Cz_1 + D| / √(A² + B² + C²)

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