RankLab
Back to Questions
PhysicsMediumMCQ2004 · Unknown

Q64.A light ray is incident perpendicular to one face of a 90∘ prism and is totally internally reflected at the glass-air interface. If the angle of reflection is 45∘ , we conclude that the refractive index n (1) n < 12 (2) n > √2 (3) n > 1 (4) n < √2 √2

What This Question Tests

This question involves applying the condition for total internal reflection in a prism, relating the critical angle to the refractive index of the glass.

Concepts Tested

Total internal reflection (TIR)Critical angleSnell's Law

Formulas Used

sin(θ_c) = 1/n

📚 NCERT Sections This Tests

9.21At What Angle Should A Ray Of Light Be Incident On The Face Of A Prism

Physics Class 12 · Chapter 9

84% match

9.21 At what angle should a ray of light be incident on the face of a prism of refracting angle 60° so that it just suffers total internal reflection at the other face? The refractive index of the material of the prism is 1.524.

9.4Figures 9.27(A) And (B) Show Refraction Of A Ray In Air Incident At 60°

Physics Class 12 · Chapter 9

83% match

9.4 Figures 9.27(a) and (b) show refraction of a ray in air incident at 60° with the normal to a glass-air and water-air interface, respectively. Predict the angle of refraction in glass when the angle of incidence in water is 45° with the normal to a water-glass interface [Fig. 9.27(c)]. FIGURE 9.27

9.17(A) Sin I¢C = 1.44/1.68 Which Gives I¢C = 59°. Total Internal Reflection

Physics Class 12 · Chapter 9

83% match

9.17 (a) sin i¢c = 1.44/1.68 which gives i¢c = 59°. Total internal reflection takes place when i > 59° or when r < rmax = 31°. Now, (sin i /sin r max max ) = 1.68 , which gives imax ~ 60°. Thus, all incident rays of angles in the range 0 < i < 60° will suffer total internal reflections in the pipe. (If the length of the pipe is finite, which it is in practice, there will be a lower limit on i determined by the ratio of the diameter to the length of the pipe.) (b) If there is no outer coating, i¢c = sin–1(1/1.68) = 36.5°. Now, i = 90° will have r = 36.5° and i¢ = 53.5° which is greater than i¢c. Thus, all incident rays (in the range 53.5° < i < 90°) will suffer total internal reflections.