Q66.Let the coefficients of three consecutive terms in the binomial expansion of (1 + 2x)n be in the ratio 2 : 5 : 8 . Then the coefficient of the term, which is in the middle of these three terms, is
What This Question Tests
This problem involves using the ratio of consecutive binomial coefficients to find the value of 'n' and then calculating a specific coefficient.
Concepts Tested
Formulas Used
Tr+1 = nCr a^(n-r) b^r
nCr/nCr-1 = (n-r+1)/r
๐ NCERT Sections This Tests
1.3 โ Define The Following Terms:
Chemistry Class 11 ยท Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
12.7 โ The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
Physics Class 12 ยท Chapter 12
12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3ร10โ11 m. What are the radii of the n = 2 and n =3 orbits?
5.28 โ How Many Ions Are Produced From The Complex Co(Nh3)6Cl2 In Solution?
Chemistry Class 11 ยท Chapter 5
5.28 How many ions are produced from the complex Co(NH3)6Cl2 in solution? (i) 6 (ii) 4 (iii) 3 (iv) 2 139 Coordination Compounds Reprint 2025-26
๐ Question Details
- Chapter
- Binomial Theorem
- Topic
- Coefficients in binomial expansion
- Year
- 2023
- Shift
- 29 Jan Shift 1
- Q Number
- Q66
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 8: Binomial Theorem
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