Q46.The freezing point of a 4% aqueous solution of X is equal to the freezing point of a 12% aqueous solution of Y . If the molecular weight of X is A , then the molecular weight of Y will be (1) 2A (2) A (3) 4A (4) 3A
What This Question Tests
This question requires applying the colligative property of freezing point depression to compare the molecular weights of two non-electrolyte solutions given their concentrations and equal freezing points.
Concepts Tested
Formulas Used
ΔTf = Kf * m
m = (w₂/M₂) * (1000/w₁)
📚 NCERT Sections This Tests
1.32 — Calculate The Depression In The Freezing Point Of Water When 10 G Of
Chemistry Class 11 · Chapter 1
1.32 Calculate the depression in the freezing point of water when 10 g of CH3CH2CHClCOOH is added to 250 g of water. Ka = 1.4 × 10–3, Kf = 1.86 K kg mol–1. 1.33 19.5 g of CH2FCOOH is dissolved in 500 g of water. The depression in the freezing point of water observed is 1.00 C. Calculate the van’t Hoff factor and dissociation constant of fluoroacetic acid.
1.3 — Define The Following Terms:
Chemistry Class 11 · Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
1.34 — Vapour Pressure Of Water At 293 K Is 17.535 Mm Hg. Calculate The Vapour
Chemistry Class 11 · Chapter 1
1.34 Vapour pressure of water at 293 K is 17.535 mm Hg. Calculate the vapour pressure of water at 293 K when 25 g of glucose is dissolved in 450 g of water.
📋 Question Details
- Chapter
- Solutions
- Topic
- Colligative properties (Freezing point depression)
- Year
- 2019
- Shift
- 12 Jan Shift 1
- Q Number
- Q46
- Type
- MCQ
- NCERT Ref
- Class 12 Chemistry Ch 2: Solutions
More from this Chapter
Q81.The orbital angular momentum for an electron revolving in an orbit is given by √l(l + 1) ⋅ 2πh . This momentum for an s-electron will be given by (1) zero (2) h 2π (3) √2 ⋅ 2πh (4) + 21 ⋅ 2πh JEE Main 2003 JEE Main Previous Year Paper
Q90.Which one of the following aqueous solutions will exhibit highest boiling point? (1) 0.01MNa2SO4 (2) 0.015M glucose (3) 0.015M urea (4) 0.01MKNO3
Q79.Two solutions of a substance (non electrolyte) are mixed in the following manner. 480 ml of 1.5 M first solution + 520 mL of 1.2 M second solution. What is the molarity of the final mixture? (1) 1.20 M (2) 1.50 M (3) 1.344 M (4) 2.70 M
Q92.Benzene and toluene form nearly ideal solutions. At 20∘C, the vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 20∘C for a solution containing 78 g of benzene and 46 g of toluene in torr is (1) 50 (2) 25 (3) 37.5 (4) 53.5