Q58.The molar solubility(s) of zirconium phosphate with molecular formula (Zr4+)3(PO3−4 )4 is given by relation : (1) Ksp 13 (2) Ksp 17 ( 9612 ) ( 6912 ) (3) Ksp 17 (4) Ksp 16 ( 8435 ) ( 5348 )
What This Question Tests
This question requires deriving the relationship between the molar solubility (s) and the solubility product (Ksp) for a sparingly soluble salt with a given complex stoichiometry.
Concepts Tested
Formulas Used
Ksp = [Zr⁴⁺]³[PO₄³⁻]⁴ = (3s)³(4s)⁴
📚 NCERT Sections This Tests
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2.8 The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm–1. Calculate its molar conductivity.
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📋 Question Details
- Chapter
- Ionic Equilibrium
- Topic
- Solubility Product (Ksp)
- Year
- 2025
- Shift
- 22 Jan Shift 2
- Q Number
- Q58
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 7: Ionic Equilibrium
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