Q86.The area of the region (in sq. units), in the first quadrant bounded by the parabola y = 9x2 and the lines x = 0, y = 1 and y = 4 , is : (1) 7/9 (2) 14/3 (3) 7/3 (4) 14/9
What This Question Tests
This question tests the ability to calculate the area of a region bounded by a parabola and horizontal lines in the first quadrant, specifically requiring integration with respect to y.
Concepts Tested
Formulas Used
Area = ∫ x dy
Equation of parabola y = 9x²
📚 NCERT Sections This Tests
9.15 — Apply Mirror Equation And The Condition:
Physics Class 12 · Chapter 9
9.15 Apply mirror equation and the condition: (a) f < 0 (concave mirror); u < 0 (object on left) (b) f > 0; u < 0 (c) f > 0 (convex mirror) and u < 0 (d) f < 0 (concave mirror); f < u < 0 to deduce the desired result.
9.5 — A Small Bulb Is Placed At The Bottom Of A Tank Containing Water To A
Physics Class 12 · Chapter 9
9.5 A small bulb is placed at the bottom of a tank containing water to a depth of 80cm. What is the area of the surface of water through which light from the bulb can emerge out? Refractive index of water is 1.33. (Consider the bulb to be a point source.)
14.2 — Which Of The Statements Given In Exercise 14.1 Is True For P-Type
Physics Class 12 · Chapter 14
14.2 Which of the statements given in Exercise 14.1 is true for p-type semiconductos.
📋 Question Details
- Chapter
- Definite Integration & Area
- Topic
- Area under curves
- Year
- 2013
- Shift
- 22 Apr Online
- Q Number
- Q86
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 8: Application of Integrals
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