Q45.Determination of the molar mass of acetic acid in benzene using freezing point depression is affected by: (1) Complex formation (2) Association (3) Partial ionization (4) Dissociation
What This Question Tests
This question tests the knowledge of factors affecting colligative properties, specifically how association of acetic acid molecules in benzene impacts the observed molar mass determined by freezing point depression.
Concepts Tested
Formulas Used
ΔTf = i * Kf * m
📚 NCERT Sections This Tests
1.32 — Calculate The Depression In The Freezing Point Of Water When 10 G Of
Chemistry Class 11 · Chapter 1
1.32 Calculate the depression in the freezing point of water when 10 g of CH3CH2CHClCOOH is added to 250 g of water. Ka = 1.4 × 10–3, Kf = 1.86 K kg mol–1. 1.33 19.5 g of CH2FCOOH is dissolved in 500 g of water. The depression in the freezing point of water observed is 1.00 C. Calculate the van’t Hoff factor and dissociation constant of fluoroacetic acid.
1.31 — The Depression In Freezing Point Of Water Observed For The Same Amount Of
Chemistry Class 11 · Chapter 1
1.31 The depression in freezing point of water observed for the same amount of acetic acid, trichloroacetic acid and trifluoroacetic acid increases in the order given above. Explain briefly.
1.34 — Vapour Pressure Of Water At 293 K Is 17.535 Mm Hg. Calculate The Vapour
Chemistry Class 11 · Chapter 1
1.34 Vapour pressure of water at 293 K is 17.535 mm Hg. Calculate the vapour pressure of water at 293 K when 25 g of glucose is dissolved in 450 g of water.
📋 Question Details
- Chapter
- Solutions
- Topic
- Colligative Properties (Freezing Point Depression)
- Year
- 2015
- Shift
- 11 Apr Online
- Q Number
- Q45
- Type
- MCQ
- NCERT Ref
- Class 12 Chemistry Ch 2: Solutions
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