Q18.In the electric network shown, when no current flows through the 4 Ω resistor in the arm EB, the potential difference between the points A and D will be: (1) 5 V (2) 3 V (3) 4 V (4) 6 V
What This Question Tests
This question involves identifying a balanced Wheatstone bridge condition (zero current through a specific resistor) and then applying Kirchhoff's laws or voltage division to find the potential difference between two points.
Concepts Tested
Formulas Used
V = IR
KCL
KVL
📚 NCERT Sections This Tests
3.2 — A Battery Of Emf 10 V And Internal Resistance 3 Ω Is Connected To A
Physics Class 11 · Chapter 3
3.2 A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistance of the resistor? What is the terminal voltage of the battery when the circuit is closed?
3.1 — The Storage Battery Of A Car Has An Emf Of 12 V. If The Internal
Physics Class 11 · Chapter 3
3.1 The storage battery of a car has an emf of 12 V. If the internal resistance of the battery is 0.4 Ω, what is the maximum current that can be drawn from the battery?
2.1 — Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At
Physics Class 11 · Chapter 2
2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
📋 Question Details
- Chapter
- Current Electricity
- Topic
- Kirchhoff's Laws and Wheatstone Bridge
- Year
- 2015
- Shift
- 11 Apr Online
- Q Number
- Q18
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 3: Current Electricity
More from this Chapter
Q50.By increasing the temperature, the specific resistance of a conductor and a semiconductor (1) increases for both (2) decreases for both (3) increases, decreases (4) decreases, increases
Q51. If in the circuit, power dissipation is 150 W, then R is (1) 2Ω (2) 6Ω (3) 5Ω (4) 4Ω JEE Main 2002 JEE Main Previous Year Paper
Q28.If θi , is the inversion temperature, θn is the neutral temperature, θc is the temperature of the cold junction, then (1) θi + θc = θn (2) θi −θc = 2θn (3) θi+θc 2 = θn (4) θc −θi = 2θn
Q47.If an ammeter is to be used in place of a voltmeter, then we must connect with the ammeter a (1) low resistance in parallel (2) high resistance in parallel (3) high resistance in series (4) low resistance in series