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PhysicsHardMCQ2020 · 09 Jan Shift 2

Q9. A small spherical droplet of density d is floating exactly half immersed in a liquid of density ρ and surface tension T. The radius of the droplet is (take note that the surface tension applies an upward force on the droplet): r = (1) r = √ 3(d+ρ)g2T (2) √ (d−ρ)gT (3) T (4) 3T r = r = √ (d+ρ)g √ (2d−ρ)g

What This Question Tests

This question involves balancing the weight of a floating droplet with the combined upward forces due to buoyancy and surface tension.

Concepts Tested

Surface tension forceBuoyant forceWeight of objectEquilibrium

Formulas Used

F_buoyancy = V_submerged * ρ_liquid * g

Weight = V_total * d_droplet * g

F_surface tension = T * (circumference)

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