Q48.The number of chiral carbons present in the molecule given below is.............. JEE Main 2020 (02 Sep Shift 1) JEE Main Previous Year Paper
What This Question Tests
This question tests the fundamental concept of identifying chiral carbon atoms in a given organic molecule. The molecule image is missing, so a general assessment is provided based on the topic.
Concepts Tested
📚 NCERT Sections This Tests
5.12 — Write All The Geometrical Isomers Of [Pt(Nh3)(Br)(Cl)(Py)] And How Many Of
Chemistry Class 11 · Chapter 5
5.12 Write all the geometrical isomers of [Pt(NH3)(Br)(Cl)(py)] and how many of these will exhibit optical isomers?
5.11 — Draw All The Isomers (Geometrical And Optical) Of:
Chemistry Class 11 · Chapter 5
5.11 Draw all the isomers (geometrical and optical) of: (i) [CoCl2(en)2] + (ii) [Co(NH3)Cl(en)2] 2+ (iii) [Co(NH3)2Cl2(en)]+
8.17 — Complete Each Synthesis By Giving Missing Starting Material, Reagent Or Products
Chemistry Class 12 · Chapter 8
8.17 Complete each synthesis by giving missing starting material, reagent or products
📋 Question Details
- Chapter
- GOC
- Topic
- Chirality
- Year
- 2020
- Shift
- 02 Sep Shift 1
- Q Number
- Q48
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 12: Organic Chemistry - Some Basic Principles and Techniques
More from this Chapter
Q33.Bond line formula of HOCH ( CN ) is: 2 (1) (2) (3) (4)
Q91.Which one the following does not have sp2 hybridized carbon? (1) Acetone (2) Acetamide (3) Acetonitrile (4) Acetic acid
Q81.The increasing order of stability of the following free radicals is (1) (CH3)2 ˙CH < (CH3)3 ˙C < (C6H5)2 ˙CH < (C6H5)3(2)˙C(C6H5)3 ˙C < (C6H5)2 ˙CH < (CH3)3 ˙C < (CH3)2 ˙CH (3) (C6H5)2 ˙CH < (C6H5)3 ˙C < (CH3)3 ˙C < (CH3)2(4)˙CH(CH3)2 ˙CH < (CH3)3 ˙C < (C6H5)3 ˙C < (C6H5)2 ˙CH
Q82.Increasing order of stability among the three main conformations (i.e. Eclipse, Anti, Gauche) of 2- fluoroethanol is (1) Eclipse, Gauche, Anti (2) Gauche, Eclipse, Anti (3) Eclipse, Anti, Gauche (4) Anti, Gauche, Eclipse JEE Main 2006 JEE Main Previous Year Paper