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PhysicsMediumMCQ2025 · 22 Jan Shift 2

Q42.A light source of wavelength λ illuminates a metal surface and electrons are ejected with maximum kinetic energy of 2 eV . If the same surface is illuminated by a light source of wavelength λ , then the maximum 2 kinetic energy of ejected electrons will be (The work function of metal is 1 eV ) (1) 3 eV (2) 2 eV (3) 6 eV (4) 5 eV

What This Question Tests

This question requires applying Einstein's photoelectric equation twice to determine the change in maximum kinetic energy with a change in the incident light's wavelength.

Concepts Tested

Photoelectric equationWork functionKinetic energy of photoelectronsWavelength and energy

Formulas Used

K_max = hc/λ - Φ

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