Q36.The products obtained during treatment of hard water using Clark's method are (1) CaCO3 and MgCO3 (2) Ca (OH)2 and Mg (OH)2 (3) CaCO3 and Mg (OH)2 (4) Ca (OH)2 and MgCO3
What This Question Tests
This question directly asks for the products formed when temporary hard water is treated using Clark's method, which involves adding calcium hydroxide.
Concepts Tested
📚 NCERT Sections This Tests
8.17 — Complete Each Synthesis By Giving Missing Starting Material, Reagent Or Products
Chemistry Class 12 · Chapter 8
8.17 Complete each synthesis by giving missing starting material, reagent or products
7.6 — Give Structures Of The Products You Would Expect When Each Of The
Chemistry Class 12 · Chapter 7
7.6 Give structures of the products you would expect when each of the following alcohol reacts with (a) HCl –ZnCl2 (b) HBr and (c) SOCl2. (i) Butan-1-ol (ii) 2-Methylbutan-2-ol
7.20 — How Are The Following Conversions Carried Out?
Chemistry Class 12 · Chapter 7
7.20 How are the following conversions carried out? (i) Propene ® Propan-2-ol. (ii) Benzyl chloride ® Benzyl alcohol. (iii) Ethyl magnesium chloride ® Propan-1-ol. (iv) Methyl magnesium bromide ® 2-Methylpropan-2-ol.
📋 Question Details
- Chapter
- Hydrogen
- Topic
- Hardness of water
- Year
- 2022
- Shift
- 28 Jul Shift 2
- Q Number
- Q36
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 9: Hydrogen
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