Q28.The graph between 1 and 1 for a thin convex lens in order to determine its focal length is plotted as shown in u v the figure. The refractive index of lens is 1. 5 and its both the surfaces have same radius of curvatures R. The value of R will be _____ cm. (Where u = object distance, v = image distance)
What This Question Tests
This problem involves interpreting a 1/v vs 1/u graph to find the focal length and then using the lens maker's formula to determine the radius of curvature.
Concepts Tested
Formulas Used
1/v - 1/u = 1/f
1/f = (n-1)(1/R₁ - 1/R₂)
📚 NCERT Sections This Tests
9.7 — Double-Convex Lenses Are To Be Manufactured From A Glass Of
Physics Class 12 · Chapter 9
9.7 Double-convex lenses are to be manufactured from a glass of refractive index 1.55, with both faces of the same radius of curvature. What is the radius of curvature required if the focal length is to be 20cm?
9.19 — A Screen Is Placed 90Cm From An Object. The Image Of The Object On
Physics Class 12 · Chapter 9
9.19 A screen is placed 90cm from an object. The image of the object on the screen is formed by a convex lens at two different locations separated by 20cm. Determine the focal length of the lens.
9.8 — A Beam Of Light Converges At A Point P. Now A Lens Is Placed In The
Physics Class 12 · Chapter 9
9.8 A beam of light converges at a point P. Now a lens is placed in the path of the convergent beam 12cm from P. At what point does the beam converge if the lens is (a) a convex lens of focal length 20cm, and (b) a concave lens of focal length 16cm?
📋 Question Details
- Chapter
- Ray Optics
- Topic
- Lens Maker's Formula
- Year
- 2022
- Shift
- 26 Jul Shift 1
- Q Number
- Q28
- Type
- Graph based
- NCERT Ref
- Class 12 Physics Ch 9: Ray Optics and Optical Instruments
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