Q71.The tangent at an extremity (in the first quadrant) of the latus rectum of the hyperbola x24 −y25 = 1 , meets the x-axis and y-axis at A and B, respectively. Then OA2 −OB2 , where O is the origin, equals (1) −209 (2) 169 (3) 4 (4) −43
What This Question Tests
The question requires finding the coordinates of the extremity of the latus rectum, then determining the equation of the tangent at that point, and finally calculating the difference of squares of its intercepts on the axes.
Concepts Tested
Formulas Used
x²/a² - y²/b² = 1
Latus rectum extremity (a e, b²/a)
Equation of tangent at (x1,y1) is xx1/a² - yy1/b² = 1
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📋 Question Details
- Chapter
- Hyperbola
- Topic
- Properties of hyperbola, tangent at latus rectum, intercepts
- Year
- 2014
- Shift
- 19 Apr Online
- Q Number
- Q71
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 11: Conic Sections
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