Q68.If the line 2x + y = k passes through the point which divides the line segment joining the points (1, 1) and (2, 4) in the ratio 3 : 2, then k equals JEE Main 2012 (Offline) JEE Main Previous Year Paper (1) 29 (2) 5 5 (3) 6 (4) 115
What This Question Tests
This question is a straightforward application of the section formula to find a point, and then substituting that point into the given line equation to find the value of k.
Concepts Tested
Formulas Used
P = ((m*x2 + n*x1)/(m+n), (m*y2 + n*y1)/(m+n))
Ax + By = C
📚 NCERT Sections This Tests
2.1 — Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At
Physics Class 11 · Chapter 2
2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
2.4 — A Spherical Conductor Of Radius 12 Cm Has A Charge Of 1.6 × 10–7C
Physics Class 11 · Chapter 2
2.4 A spherical conductor of radius 12 cm has a charge of 1.6 × 10–7C distributed uniformly on its surface. What is the electric field (a) inside the sphere (b) just outside the sphere (c) at a point 18 cm from the centre of the sphere?
2.9 — The Resistance Of A Conductivity Cell Containing 0.001M Kcl Solution At 298
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2.9 The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 W. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10–3 S cm–1. 59 Electrochemistry Reprint 2025-26
📋 Question Details
- Chapter
- Straight Lines
- Topic
- Section Formula, Equation of a line
- Year
- 2012
- Shift
- Offline
- Q Number
- Q68
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 10: Straight Lines
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