Q35.When the hydrogen ion concentration [H+]changes by a factor of 1000 , the value of pH of the solution (1) increases by 1000 units (2) decreases by 3 units (3) decreases by 2 units (4) increases by 2 units
What This Question Tests
This multi-step question requires setting up and solving a system of equations based on stoichiometry of combustion and ideal gas law, then calculating total heat evolved.
Concepts Tested
Formulas Used
PV = nRT
Heat evolved = Σ(moles × ΔH_c)
📚 NCERT Sections This Tests
1.27 — If The Solubility Product Of Cus Is 6 × 10–16, Calculate The Maximum Molarity Of
Chemistry Class 11 · Chapter 1
1.27 If the solubility product of CuS is 6 × 10–16, calculate the maximum molarity of CuS in aqueous solution.
1.35 — Henry’S Law Constant For The Molality Of Methane In Benzene At 298 K Is
Chemistry Class 11 · Chapter 1
1.35 Henry’s law constant for the molality of methane in benzene at 298 K is 4.27 × 105 mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.
4.14 — Describe The Preparation Of Potassium Dichromate From Iron Chromite Ore.
Chemistry Class 11 · Chapter 4
4.14 Describe the preparation of potassium dichromate from iron chromite ore. What is the effect of increasing pH on a solution of potassium dichromate?
📋 Question Details
- Chapter
- Thermodynamics & Thermochemistry
- Topic
- Heat of Combustion
- Year
- 2023
- Shift
- 25 Jan Shift 2
- Q Number
- Q35
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 6: Thermodynamics & Thermochemistry
More from this Chapter
Q89.A heat engine absorbs heat Q1 at temperature T1 and heat Q2 at temperature T2 . Work done by the engine is J (Q1 + Q2). This data (1) violates 1st law of thermodynamics (2) violates 1st law of thermodynamics if Q1 is −ve (3) violates 1st law of thermodynamics if Q2 is − ve(4) does not violate 1st law of thermodynamics
Q93.If at 298 K the bond energies of C −H, C −C, C = C and H −H bonds are respectively 414, 347, 615 and 435 kJ mol−1 , the value of enthalpy change for the reaction H2C = CH2( g) + H2( g) →H3C −CH3( g) at 298 K will be (1) −250 kJ (2) +125 kJ (3) −125 kJ (4) +250 kJ
Q94.In an irreversible process taking place at constant T and P and in which only pressure-volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS), satisfy the criteria (1) (dS)V,E > 0, (dG)T,P < 0 (2) (dS)V:E = 0, (dG)TPP = 0 (3) (dS)V,E = 0, (dG)T,P > 0 (4) (dS)V,E < 0, (dG)T,P < 0
Q96.The enthalpy change for a reaction does not depend upon (1) use of different reactants for the same product (2) the nature of intermediate reaction steps (3) the differences in initial or final temperatures of (4) the physical states of reactants and products involved substances