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PhysicsMediumMCQ2021 · 17 Mar Shift 1

Q16.An electron of mass m and a photon have same energy E. The ratio of wavelength of electron to that of photon is : ( c being the velocity of light) (1) 1 2m 21 (2) 1 E 12 c ( E ) c ( 2m ) (3) E 21 (4) c(2mE) 12 ( 2 m )

What This Question Tests

This question tests the ability to derive and compare the de Broglie wavelength for an electron with the wavelength of a photon, given they have the same energy.

Concepts Tested

De Broglie wavelengthPhoton energyMomentum of photon and electron

Formulas Used

λ_e = h/p_e

KE = p_e²/(2m)

λ_ph = hc/E

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