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PhysicsMediumNumerical2003 · Unknown

Q74.A nucleus with Z = 92 emits the following in a sequence: α, β−, β−α, α, α, α, α, β−, β−, α, β+, β+, α. Then Z of the resulting nucleus is (1) 76 (2) 78 (3) 82 (4) 74

What This Question Tests

This question involves systematically tracking the change in atomic number (Z) through a sequence of alpha, beta-minus, and beta-plus decays. Based on the literal reading of the decay sequence, the final Z is calculated to be 80, which is not among the given options.

Concepts Tested

Alpha decay (Z change)Beta-minus decay (Z change)Beta-plus decay (Z change)

Formulas Used

α-decay: Z -> Z-2

β⁻-decay: Z -> Z+1

β⁺-decay: Z -> Z-1

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