Q88.The shortest distance between the lines x 2 = 2y = 1z and x+2−1 = y−48 = z−54 , lies in the interval: (1) (3, 4] (2) (2, 3] (3) [1, 2) (4) [0, 1)
What This Question Tests
This problem requires finding the shortest distance between two skew lines given in Cartesian form. It involves converting them to vector form, calculating the cross product of direction vectors, and applying the shortest distance formula.
Concepts Tested
Formulas Used
Line in vector form: r = a + λb
Shortest distance = |(a₂ - a₁) · (b₁ x b₂)| / |b₁ x b₂|
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📋 Question Details
- Chapter
- 3D Geometry
- Topic
- Shortest distance between skew lines
- Year
- 2016
- Shift
- 09 Apr Online
- Q Number
- Q88
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 11: Three Dimensional Geometry
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