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PhysicsMediumMCQ2018 · 08 Apr

Q6. It is found that if a neutron suffers an elastic collinear collision with a deuterium at rest, the fractional loss of its energy is Pd , while for its similar collision with a carbon nucleus at rest, the fractional loss of energy is Pc . The values of Pd and Pc are respectively (1) 0, 1 (2) 0. 89, 0. 28 (3) 0. 28, 0. 89 (4) 0, 0

What This Question Tests

This question applies the formula for fractional energy loss of an incident particle in a 1D elastic collision, requiring knowledge of the approximate masses of the colliding nuclei.

Concepts Tested

One-dimensional elastic collisionFractional energy loss formulaAtomic masses

Formulas Used

K_f/K_i = ((m₁ - m₂)/(m₁ + m₂))²

Fractional loss = 1 - (K_f/K_i)

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