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PhysicsMediumNumerical2023 ยท 01 Feb Shift 1

Q29.A thin cylindrical rod of length 10 cm is placed horizontally on the principle axis of a concave mirror of focal length 20 cm. The rod is placed in a such a way that mid point of the rod is at 40 cm from the pole of mirror. The length of the image formed by the mirror will be ๐‘ฅ cm. The value of ๐‘ฅ is ______. 3

What This Question Tests

This question requires applying the mirror formula and understanding longitudinal magnification to find the length of the image of a rod placed on the principal axis of a concave mirror.

Concepts Tested

Mirror formulaMagnificationLongitudinal magnification

Formulas Used

1/f = 1/v + 1/u

m = -v/u

Length of image = vโ‚‚ - vโ‚

๐Ÿ“š NCERT Sections This Tests

9.1 โ€” A Small Candle, 2.5 Cm In Size Is Placed At 27 Cm In Front Of A Concave

Physics Class 12 ยท Chapter 9

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9.1 A small candle, 2.5 cm in size is placed at 27 cm in front of a concave mirror of radius of curvature 36 cm. At what distance from the mirror should a screen be placed in order to obtain a sharp image? Describe the nature and size of the image. If the candle is moved closer to the mirror, how would the screen have to be moved?

9.2 โ€” A 4.5 Cm Needle Is Placed 12 Cm Away From A Convex Mirror Of Focal

Physics Class 12 ยท Chapter 9

80% match

9.2 A 4.5 cm needle is placed 12 cm away from a convex mirror of focal length 15 cm. Give the location of the image and the magnification. Describe what happens as the needle is moved farther from the mirror.

9.15 โ€” Apply Mirror Equation And The Condition:

Physics Class 12 ยท Chapter 9

79% match

9.15 Apply mirror equation and the condition: (a) f < 0 (concave mirror); u < 0 (object on left) (b) f > 0; u < 0 (c) f > 0 (convex mirror) and u < 0 (d) f < 0 (concave mirror); f < u < 0 to deduce the desired result.