Q80.A pair of dice is thrown 5 times. For each throw, a total of 5 is considered a success. If the probability of at ๐ is equal to least 4 successes is 311,๐ then (1) 82 (2) 75 (3) 164 (4) 123
What This Question Tests
The question requires calculating the probability of a success in a single throw of dice, then applying the binomial probability distribution to find the probability of at least 4 successes in 5 throws.
Concepts Tested
Formulas Used
P(X=r) = nCr * p^r * q^(n-r)
P(at least k successes) = P(X=k) + P(X=k+1) + ... + P(X=n)
๐ NCERT Sections This Tests
2.5 โ A Parallel Plate Capacitor With Air Between The Plates Has A
Physics Class 11 ยท Chapter 2
2.5 A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1pF = 10โ12 F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6?
11.6 โ The Threshold Frequency For A Certain Metal Is 3.3 ร 1014 Hz. If Light
Physics Class 12 ยท Chapter 11
11.6 The threshold frequency for a certain metal is 3.3 ร 1014 Hz. If light of frequency 8.2 ร 1014 Hz is incident on the metal, predict the cut- off voltage for the photoelectric emission.
2.1 โ Two Charges 5 ร 10โ8 C And โ3 ร 10โ8 C Are Located 16 Cm Apart. At
Physics Class 11 ยท Chapter 2
2.1 Two charges 5 ร 10โ8 C and โ3 ร 10โ8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
๐ Question Details
- Chapter
- Probability
- Topic
- Binomial probability distribution
- Year
- 2023
- Shift
- 06 Apr Shift 1
- Q Number
- Q80
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 13: Probability
More from this Chapter
Q90.One ticket is selected at random from 50 tickets numbered 00, 01, 02, โฆ , 49. Then the probability that the sum of the digits on the selected ticket is 8 , given that the product of these digits is zero, equals (1) 1 (2) 1 14 7 (3) 5 (4) 1 14 50 JEE Main 2009 JEE Main Previous Year Paper
Q89.Four numbers are chosen at random (without replacement) from the set {1, 2, 3, โฆ . , 20} . Statement-1: The probability that the chosen numbers when arranged in some order will form an AP is 1 . Statement-2: If the 85 four chosen numbers from an AP, then the set of all possible values of common difference is {ยฑ1, ยฑ2, ยฑ3, ยฑ4, ยฑ5}. (1) Statement-1 is true, Statement-2 is true; (2) Statement-1 is true, Statement-2 is false Statement-2 is not the correct explanation for Statement-1 (3) Statement-1 is false, Statement-2 is true (4) Statement-1 is true, Statement-2 is true; Statement-2 is the correct explanation for Statement-1
Q90.An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colour is (1) 2 (2) 1 7 21 (3) 2 (4) 1 23 3 JEE Main 2010 JEE Main Previous Year Paper
Q89.Consider 5 independent Bernoulli's trials each with probability of success p . If the probability of at least one failure is greater than or equal to 31 , then p lies in the interval 32 (1) ( 34 , 1112 ] (2) [0, 12 ] (3) ( 1112 , 1] (4) ( 12 , 34 ]