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MathsEasyMCQ2015 · 10 Apr Online

Q88.If the points (1, 1, λ) & (−3, 0, 1), are equidistant from the plane, 3x + 4y −12z + 13 = 0, then λ satisfies the equation: (1) 3x2 + 10x + 7 = 0 (2) 3x2 + 10x −13 = 0 (3) 3x2 −10x + 7 = 0 (4) 3x2 −10x + 21 = 0 JEE Main 2015 (10 Apr Online) JEE Main Previous Year Paper

What This Question Tests

This is a direct application of the formula for the distance of a point from a plane. By equating the distances of two given points from the plane, an equation in terms of lambda is formed, which needs to be solved.

Concepts Tested

Distance of a point from a planeEquation of a plane

Formulas Used

Distance = |Ax₁ + By₁ + Cz₁ + D| / √(A² + B² + C²)

📚 NCERT Sections This Tests

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