Q34.The species in which the N atom is a state of sp hybridization is: (1) NO−3 (2) NO2 (3) NO+2 (4) NO−2
What This Question Tests
This question requires determining the hybridization of the central nitrogen atom in different species by drawing Lewis structures and calculating the steric number.
Concepts Tested
Formulas Used
Steric Number = (Number of sigma bonds + Number of lone pairs)
📚 NCERT Sections This Tests
5.15 — Discuss The Nature Of Bonding In The Following Coordination Entities On The
Chemistry Class 11 · Chapter 5
5.15 Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory: (i) [Fe(CN)6] 4– (ii) [FeF6] 3– (iii) [Co(C2O4)3]3– (iv) [CoF6] 3–
5.16 — Draw Figure To Show The Splitting Of D Orbitals In An Octahedral Crystal Field.
Chemistry Class 11 · Chapter 5
5.16 Draw figure to show the splitting of d orbitals in an octahedral crystal field.
5.18 — What Is Crystal Field Splitting Energy? How Does The Magnitude Of Do Decide
Chemistry Class 11 · Chapter 5
5.18 What is crystal field splitting energy? How does the magnitude of Do decide the actual configuration of d orbitals in a coordination entity?
📋 Question Details
- Chapter
- Chemical Bonding
- Topic
- Hybridization
- Year
- 2016
- Shift
- 03 Apr
- Q Number
- Q34
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 4: Chemical Bonding and Molecular Structure
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