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MathsHardNumerical2024 · 04 Apr Shift 1

Q81.Let a = 1 + 2C23! + 3C24! + 4C25! + … 1! + 2! + 3! + … Then 2b is equal to a2

What This Question Tests

This question involves evaluating two complex series, 'a' and 'b', which require manipulation of binomial coefficients and factorials before finding the value of the requested expression.

Concepts Tested

Series summation using combinatoricsBinomial coefficientsFactorial properties

Formulas Used

nCr = n! / (r! * (n-r)!)

Σ nCr = 2^n

1/k! = (k+1-1)/k!

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