Q58.The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to h2 . The value of x ma20 10 x is ( a0 is radius of Bohr's orbit) (Nearest integer) [Given: Ο = 3. 14]
What This Question Tests
This question involves calculating the temperature change during a neutralization reaction, requiring determination of the limiting reactant and using specific heat capacity to relate heat released to temperature change.
Concepts Tested
Formulas Used
q = m * s * ΞT
Heat = moles of limiting reagent * molar heat of neutralization
π NCERT Sections This Tests
12.4 β The Ground State Energy Of Hydrogen Atom Is β13.6 Ev. What Are The
Physics Class 12 Β· Chapter 12
12.4 The ground state energy of hydrogen atom is β13.6 eV. What are the kinetic and potential energies of the electron in this state?
12.5 β A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 Β· Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.7 β The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
Physics Class 12 Β· Chapter 12
12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3Γ10β11 m. What are the radii of the n = 2 and n =3 orbits?
π Question Details
- Chapter
- Thermodynamics & Thermochemistry
- Topic
- Heat of neutralization
- Year
- 2021
- Shift
- 27 Aug Shift 1
- Q Number
- Q58
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 6: Thermodynamics
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