Q46.In Friedel-Crafts alkylation of aniline, one gets: (1) alkylated product with ortho and (2) secondary amine after acidic treatment. para substitution. (3) an amide product. (4) positively charged nitrogen at benzene ring.
What This Question Tests
This question tests the specific knowledge of how aniline reacts under Friedel-Crafts alkylation conditions, specifically the deactivation of the ring due to salt formation with the Lewis acid catalyst.
Concepts Tested
📚 NCERT Sections This Tests
9.8 — Accomplish The Following Conversions:
Chemistry Class 12 · Chapter 9
9.8 Accomplish the following conversions: (i) Nitrobenzene to benzoic acid (ii) Benzene to m-bromophenol (iii) Benzoic acid to aniline (iv) Aniline to 2,4,6-tribromofluorobenzene (v) Benzyl chloride to 2-phenylethanamine (vi) Chlorobenzene to p-chloroaniline (vii) Aniline to p-bromoaniline (viii) Benzamide to toluene (ix) Aniline to benzyl alcohol.
9.7 — Write Short Notes On The Following:
Chemistry Class 12 · Chapter 9
9.7 Write short notes on the following: (i) Carbylamine reaction (ii) Diazotisation (iii) Hofmann’s bromamide reaction (iv) Coupling reaction (v) Ammonolysis (vi) Acetylation (vii) Gabriel phthalimide synthesis.
7.16 — Explain How Does The –Oh Group Attached To A Carbon Of Benzene Ring
Chemistry Class 12 · Chapter 7
7.16 Explain how does the –OH group attached to a carbon of benzene ring activate it towards electrophilic substitution?
📋 Question Details
- Chapter
- Nitrogen Compounds
- Topic
- Reactions of anilines
- Year
- 2022
- Shift
- 29 Jun Shift 2
- Q Number
- Q46
- Type
- MCQ
- NCERT Ref
- Class 12 Chemistry Ch 13: Nitrogen Compounds
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