Q19.An electron having de-Broglie wavelength λ is incident on a target in a X -ray tube. Cut-off wavelength of emitted X -ray is: (1) 0 (2) 2 m2c2λ2 h2 (3) 2mcλ2 (4) hc h mc
What This Question Tests
This question connects the de-Broglie wavelength of an electron to its kinetic energy, which is then converted into X-ray photon energy to find the cut-off wavelength.
Concepts Tested
Formulas Used
λ_deBroglie = h/p
KE = p^2/(2m)
KE = eV
E_photon = hc/λ_cutoff
📚 NCERT Sections This Tests
12.8 — A 12.5 Ev Electron Beam Is Used To Bombard Gaseous Hydrogen At
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12.8 A 12.5 eV electron beam is used to bombard gaseous hydrogen at room temperature. What series of wavelengths will be emitted?
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11.3 The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted?
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📋 Question Details
- Chapter
- Dual Nature of Matter
- Topic
- De Broglie wavelength and X-ray production
- Year
- 2021
- Shift
- 20 Jul Shift 2
- Q Number
- Q19
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 11: Dual Nature of Radiation and Matter
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