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MathsHardMCQ2014 · 06 Apr

Q71.The locus of the foot of perpendicular drawn from the centre of the ellipse x2 + 3y2 = 6 on any tangent to it is (1) (x2 + y2) 2 = 6x2 + 2y2 (2) (x2 + y2) 2 = 6x2 −2y2 (3) (x2 −y2) 2 = 6x2 + 2y2 (4) (x2 −y2) 2 = 6x2 −2y2

What This Question Tests

This is a challenging locus problem involving the pedal curve of an ellipse, requiring parametric equations of tangents and perpendicularity conditions from the center.

Concepts Tested

Equation of an ellipseEquation of tangent to ellipsePerpendicular linesLocus of a point

Formulas Used

x²/a² + y²/b² = 1

Tangent x/a cosθ + y/b sinθ = 1

Slope of perpendicular lines m1m2 = -1

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