Q68.If a straight line passing through the point P(−3, 4) is such that its intercepted portion between the coordinate axes is bisected at P , then its equation is : (1) 4x + 3y = 0 (2) 4x −3y + 24 = 0 (3) 3x −4y + 25 = 0 (4) x −y + 7 = 0
What This Question Tests
This question is a direct application of the intercept form of a straight line and the midpoint formula to find the equation of the line.
Concepts Tested
Formulas Used
x/a + y/b = 1
Midpoint = ((x1+x2)/2, (y1+y2)/2)
📚 NCERT Sections This Tests
2.1 — Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At
Physics Class 11 · Chapter 2
2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
9.8 — A Beam Of Light Converges At A Point P. Now A Lens Is Placed In The
Physics Class 12 · Chapter 9
9.8 A beam of light converges at a point P. Now a lens is placed in the path of the convergent beam 12cm from P. At what point does the beam converge if the lens is (a) a convex lens of focal length 20cm, and (b) a concave lens of focal length 16cm?
9.15 — Apply Mirror Equation And The Condition:
Physics Class 12 · Chapter 9
9.15 Apply mirror equation and the condition: (a) f < 0 (concave mirror); u < 0 (object on left) (b) f > 0; u < 0 (c) f > 0 (convex mirror) and u < 0 (d) f < 0 (concave mirror); f < u < 0 to deduce the desired result.
📋 Question Details
- Chapter
- Straight Lines
- Topic
- Equation of a line from intercepted segment properties
- Year
- 2019
- Shift
- 12 Jan Shift 2
- Q Number
- Q68
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 10: Straight Lines
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