Q68.A triangle has a vertex at (1, 2) and the mid points of the two sides through it are (โ1, 1) and (2, 3) . Then the centroid of this triangle is: (1) ( 31 , 1) (2) (1, 73 ) (3) ( 31 , 2) (4) ( 13 , 35 )
What This Question Tests
This question tests the basic understanding of coordinate geometry, specifically using the midpoint formula to find the coordinates of the other vertices and then applying the centroid formula.
Concepts Tested
Formulas Used
Midpoint = ((x1+x2)/2, (y1+y2)/2)
Centroid = ((x1+x2+x3)/3, (y1+y2+y3)/3)
๐ NCERT Sections This Tests
2.2 โ A Regular Hexagon Of Side 10 Cm Has A Charge 5 Mc At Each Of Its
Physics Class 11 ยท Chapter 2
2.2 A regular hexagon of side 10 cm has a charge 5 mC at each of its vertices. Calculate the potential at the centre of the hexagon.
2.1 โ Two Charges 5 ร 10โ8 C And โ3 ร 10โ8 C Are Located 16 Cm Apart. At
Physics Class 11 ยท Chapter 2
2.1 Two charges 5 ร 10โ8 C and โ3 ร 10โ8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
1.18 โ A Point Charge Of 2.0 Mc Is At The Centre Of A Cubic Gaussian
Physics Class 11 ยท Chapter 1
1.18 A point charge of 2.0 mC is at the centre of a cubic Gaussian surface 9.0 cm on edge. What is the net electric flux through the surface?
๐ Question Details
- Chapter
- Coordinate Geometry
- Topic
- Triangle properties
- Year
- 2019
- Shift
- 12 Apr Shift 2
- Q Number
- Q68
- Type
- MCQ
- NCERT Ref
- Class 10 Mathematics Ch 7: Coordinate Geometry
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