Q31.What would be the molality of 20% (mass/mass) aqueous solution of KI ? (molar mass of KI = 166 g mol−1 ) (1) 1.35 (2) 1.51 (3) 1.08 (4) 1.48
What This Question Tests
This question tests the basic calculation of molality from mass percentage, requiring conversion of mass percentage to mass of solute and solvent, then using the molar mass to find moles.
Concepts Tested
Formulas Used
Molality (m) = moles of solute / mass of solvent (in kg)
📚 NCERT Sections This Tests
1.3 — Define The Following Terms:
Chemistry Class 11 · Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
2.8 — The Conductivity Of 0.20 M Solution Of Kcl At 298 K Is 0.0248 S Cm–1. Calculate
Chemistry Class 11 · Chapter 2
2.8 The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm–1. Calculate its molar conductivity.
1.28 — Calculate The Mass Percentage Of Aspirin (C9H8O4) In Acetonitrile (Ch3Cn) When
Chemistry Class 11 · Chapter 1
1.28 Calculate the mass percentage of aspirin (C9H8O4) in acetonitrile (CH3CN) when 6.5 g of C9H8O4 is dissolved in 450 g of CH3CN.
📋 Question Details
- Chapter
- Solutions
- Topic
- Concentration terms
- Year
- 2019
- Shift
- 09 Apr Shift 2
- Q Number
- Q31
- Type
- MCQ
- NCERT Ref
- Class 12 Chemistry Ch 2: Solutions
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