Q47.The electrode potential of the following half cell at 298 K X X2+(0. 001M)∥Y2+(0. 01M) Y is _____ ×10−2 V (Nearest integer) Given : E0 = −2. 36 V X2+∣X E0 = +0. 36 V Y2+Y 2.303 RT = 0. 06 V F
What This Question Tests
This question requires calculating the cell potential using the Nernst equation, given standard electrode potentials and ion concentrations.
Concepts Tested
Formulas Used
Ecell = E°cell - (0.06 / n) * log(Q)
E°cell = E°cathode - E°anode
📚 NCERT Sections This Tests
2.4 — Calculate The Standard Cell Potentials Of Galvanic Cell In Which The Following
Chemistry Class 11 · Chapter 2
2.4 Calculate the standard cell potentials of galvanic cell in which the following reactions take place: (i) 2Cr(s) + 3Cd2+(aq) ® 2Cr3+(aq) + 3Cd (ii) Fe2+(aq) + Ag+(aq) ® Fe3+(aq) + Ag(s) Calculate the DrGo and equilibrium constant of the reactions. 2.5 Write the Nernst equation and emf of the following cells at 298 K: (i) Mg(s)|Mg2+(0.001M)||Cu2+(0.0001 M)|Cu(s) (ii) Fe(s)|Fe2+(0.001M)||H+(1M)|H2(g)(1bar)| Pt(s) (iii) Sn(s)|Sn2+(0.050 M)||H+(0.020 M)|H2(g) (1 bar)|Pt(s) (iv) Pt(s)|Br–(0.010 M)|Br2(l )||H+(0.030 M)| H2(g) (1 bar)|Pt(s).
2.2 — Given The Standard Electrode Potentials,
Chemistry Class 11 · Chapter 2
2.2 Given the standard electrode potentials, K+/K = –2.93V, Ag+/Ag = 0.80V, Hg2+/Hg = 0.79V Mg2+/Mg = –2.37 V, Cr3+/Cr = – 0.74V Arrange these metals in their increasing order of reducing power.
2.9 — The Resistance Of A Conductivity Cell Containing 0.001M Kcl Solution At 298
Chemistry Class 11 · Chapter 2
2.9 The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 W. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10–3 S cm–1. 59 Electrochemistry Reprint 2025-26
📋 Question Details
- Chapter
- Electrochemistry
- Topic
- Nernst equation
- Year
- 2023
- Shift
- 30 Jan Shift 2
- Q Number
- Q47
- Type
- Numerical
- NCERT Ref
- Class 12 Chemistry Ch 3: Electrochemistry
More from this Chapter
Q58.The mass of product liberated on anode in an electrochemical cell depends on (where t is the time period, for which the current is passed) (1) (It)1/2 (2) IT (3) I/t (4) I2t
Q48.The negative Zn pole of a Daniell cell, sending a constant current through a circuit, decreases in mass by 0.13 g in 30 minutes. If the electrochemical equivalent of Zn and Cu are 32.5 and 31.5 respectively, the increase in the mass of the positive Cu pole in this time is (1) 0.180 g (2) 0.141 g (3) 0.126 g (4) 0.242 g
Q49.The electrochemical equivalent of a metal is 3.3 × 10−7 kg per coulomb. The mass of the metal liberated at the cathode when a 3 A current is passed for 2 seconds will be (1) 19.8 × 10−7 kg (2) 9.9 × 10−7 kg (3) 6.6 × 10−7 kg (4) 1.1 × 10−7 kg
Q46.Two voltameters one of copper and another of silver, are joined in parallel. When a total charge q flows through the voltameters, equal amount of metals are deposited. If the electrochemical equivalents of copper and silver are z1 and z2 respectively the charge which flows through the silver voltameter is (1) q z1 (2) q z2 1+ 1+ z2 z1 (3) q z1 (4) q z2 z2 z1