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MathsMediumMCQ2020 · 09 Jan Shift 1

Q68.If f '(x) = tan−1(sec x + tan x), −π2 < x < π2 and f(0) = 0 , then f(1) is equal to: (1) π+1 (2) 1 4 4 (3) π−1 (4) π+2 4 4

What This Question Tests

The problem tests the ability to simplify a trigonometric expression using identities, apply properties of inverse trigonometric functions, and then integrate the resulting function to find f(x) using the given initial condition.

Concepts Tested

Indefinite IntegrationTrigonometric identitiesInverse trigonometric functionsInitial value problems

Formulas Used

sec x + tan x = tan(π/4 + x/2)

∫(ax + b)dx = ax²/2 + bx + C

tan⁻¹(tan θ) = θ for θ ∈ (-π/2, π/2)

📚 NCERT Sections This Tests

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