Q72.The system of equations kx + y + z = 1, x + ky + z = k and x + y + zk = k2 has no solution if k is equal to: (1) 0 (2) 1 (3) −1 (4) −2
What This Question Tests
This question tests the conditions for a system of linear equations to have no solution, primarily using determinants of the coefficient matrix and associated matrices.
Concepts Tested
Formulas Used
For no solution: det(A) = 0 and at least one det(A_i) ≠ 0
📚 NCERT Sections This Tests
1.3 — Define The Following Terms:
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1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
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1.27 If the solubility product of CuS is 6 × 10–16, calculate the maximum molarity of CuS in aqueous solution.
1.1 — Define The Term Solution. How Many Types Of Solutions Are Formed? Write Briefly
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1.1 Define the term solution. How many types of solutions are formed? Write briefly about each type with an example.
📋 Question Details
- Chapter
- Matrices & Determinants
- Topic
- System of linear equations (Cramer's rule/Determinant method)
- Year
- 2021
- Shift
- 17 Mar Shift 1
- Q Number
- Q72
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 4: Determinants
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