Q53.The number of molecules/ion/s having trigonal bipyramidal shape is …….. . PF5, BrF5, PCl5, PtCl4 2 - , BF3, Fe(CO ) 5
What This Question Tests
This question requires applying VSEPR theory and hybridization concepts to determine the molecular geometry of various given species and identify those with a trigonal bipyramidal shape.
Concepts Tested
Formulas Used
Steric number = number of bond pairs + number of lone pairs
📚 NCERT Sections This Tests
5.12 — Write All The Geometrical Isomers Of [Pt(Nh3)(Br)(Cl)(Py)] And How Many Of
Chemistry Class 11 · Chapter 5
5.12 Write all the geometrical isomers of [Pt(NH3)(Br)(Cl)(py)] and how many of these will exhibit optical isomers?
5.15 — Discuss The Nature Of Bonding In The Following Coordination Entities On The
Chemistry Class 11 · Chapter 5
5.15 Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory: (i) [Fe(CN)6] 4– (ii) [FeF6] 3– (iii) [Co(C2O4)3]3– (iv) [CoF6] 3–
5.11 — Draw All The Isomers (Geometrical And Optical) Of:
Chemistry Class 11 · Chapter 5
5.11 Draw all the isomers (geometrical and optical) of: (i) [CoCl2(en)2] + (ii) [Co(NH3)Cl(en)2] 2+ (iii) [Co(NH3)2Cl2(en)]+
📋 Question Details
- Chapter
- Chemical Bonding
- Topic
- VSEPR Theory and Molecular Geometry
- Year
- 2024
- Shift
- 01 Feb Shift 1
- Q Number
- Q53
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 4: Chemical Bonding and Molecular Structure
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