Q60.The number of optical isomers possible for [Cr (C2O4)3]3− is:
What This Question Tests
This question requires calculating the molar conductivity of a solution from its resistance, cell constant, and concentration, applying fundamental electrochemistry formulas.
Concepts Tested
Formulas Used
G = 1/R
κ = G * G*
Λm = κ * 1000 / C (in S cm2 mol-1)
📚 NCERT Sections This Tests
2.9 — The Resistance Of A Conductivity Cell Containing 0.001M Kcl Solution At 298
Chemistry Class 11 · Chapter 2
2.9 The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 W. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10–3 S cm–1. 59 Electrochemistry Reprint 2025-26
2.7 — Define Conductivity And Molar Conductivity For The Solution Of An Electrolyte.
Chemistry Class 11 · Chapter 2
2.7 Define conductivity and molar conductivity for the solution of an electrolyte. Discuss their variation with concentration.
5.12 — Write All The Geometrical Isomers Of [Pt(Nh3)(Br)(Cl)(Py)] And How Many Of
Chemistry Class 11 · Chapter 5
5.12 Write all the geometrical isomers of [Pt(NH3)(Br)(Cl)(py)] and how many of these will exhibit optical isomers?
📋 Question Details
- Chapter
- Electrochemistry
- Topic
- Molar conductivity
- Year
- 2021
- Shift
- 27 Aug Shift 2
- Q Number
- Q60
- Type
- Numerical
- NCERT Ref
- Class 12 Chemistry Ch 3: Electrochemistry
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