Q51. Consider the above reaction where 6. 1 g of benzoic acid is used to get 7. 8 g of m-bromo benzoic acid. The percentage yield of the product is ___ . (Round off to the Nearest integer) [Given : Atomic masses : C = 12. 0 u, H : 1. 0 u, O : 16. 0 u, Br = 80. 0 u ]
What This Question Tests
This question combines the knowledge of electrophilic aromatic substitution (bromination of benzoic acid to form m-bromo benzoic acid) with a calculation of the percentage yield using given masses and atomic weights.
Concepts Tested
Formulas Used
Percentage yield = (Actual yield / Theoretical yield) * 100
Molar mass calculation
📚 NCERT Sections This Tests
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1.30 Calculate the amount of benzoic acid (C6H5COOH) required for preparing 250 mL of 0.15 M solution in methanol.
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9.8 Accomplish the following conversions: (i) Nitrobenzene to benzoic acid (ii) Benzene to m-bromophenol (iii) Benzoic acid to aniline (iv) Aniline to 2,4,6-tribromofluorobenzene (v) Benzyl chloride to 2-phenylethanamine (vi) Chlorobenzene to p-chloroaniline (vii) Aniline to p-bromoaniline (viii) Benzamide to toluene (ix) Aniline to benzyl alcohol.
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1.28 Calculate the mass percentage of aspirin (C9H8O4) in acetonitrile (CH3CN) when 6.5 g of C9H8O4 is dissolved in 450 g of CH3CN.
📋 Question Details
- Chapter
- Organic: Haloalkanes & Haloarenes
- Topic
- Electrophilic aromatic substitution
- Year
- 2021
- Shift
- 18 Mar Shift 2
- Q Number
- Q51
- Type
- Numerical
- NCERT Ref
- Class 12 Chemistry Ch 10: Haloalkanes and Haloarenes
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